Question

The circumference of the base of a cylindrical
vessel is 132 cm and its height is 25 cm.
How many litres
of water can it hold?
(1000cm = 1L)​

Answer 1

Given :-

• The circumference of the base of a cylindrical vessel is 132 cm.

• Its height is 25 cm.

To find :-

• How many litres of water can it hold.

Solution :-

Circumference of base=2πr

The circumference of the cylindrical vessel is 132 cm.

According to the question,

→2πr = 132

→ 2 × (22/7) × r = 132

→ r = 132 × ½ × (7/22)

→ r = 21

Radius of the cylindrical vessel is 21 cm.

Volume of cylindrical vessel = πr²h

= [ (22/7) × 21× 21 × 25 ] cm³

= (22 × 3 × 21 × 25) cm³

$\implies$ 34650 cm³

Converting 34650 into litres -

→ 34650/1000

$\implies$ 34.65 L

$\therefore$ The vessel can hold 34.65 Litres of water.

____________________________________________

Answer 2

Answer:

Given:-

The circumference of the base of a cylindrical vessel is 132 cm and it's height is 25 cm .

To Find:-

• How many litres of water can it hold .

Solution :-

The circumference of the base of cylindrical vessel is 132 cm.

We know that,

Circumference = 2πr

ATQ :-

↬ 2πr = 132

↬ 2 × $\dfrac{22}{7}$ × r = 132

↬ r = 132 × $\dfrac{1}{2} × \dfrac{7}{22}$

↬ r = 66 × $\dfrac{7}{22}$

➥ r = 21 cm

Now, we know that,

Volume = πr²h

We get,

• r = 21 cm
• h = 25 cm

⇨ $\dfrac{22}{7} × (21)² × 25$

⇨ $\dfrac{22}{7} × 21 × 21 × 25$

⇨ $\dfrac{22}{7} × 11025$

➙ 34650 cm³

Now, in question given that (1000 cm = 1L)

Then,

☞ $\dfrac{34650}{1000}$

✏ 34.65 L

Therefore, 34.65 L of water can be hold.