Question

the circumference of the base of a cylindrical vessel is 132 cm and it's height is 25 cm. find its volume.(use π=22/7)​

Answer 1

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Let radius as r.

Circumference = 2πr

$\\ 132 = 2 \times \frac{22}{7} \times r \\ \\ \frac{132 \times 7}{22 \times 2} = r \\ \\ r = 21 \: cm$

Volume of cyclinderical :-

$= \pi {r}^{2} h \\ \\ = \frac{22}{7} \times 21 \times 21 \times 25 \\ \\ = 34650 { \: cm}^{ 3}$

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Answer 2

Here is your answer:

Circumference of the base of the vessel

= 132cm

Formula of the circumference of a circle :

$2\pi {r}$

Therfore,

$2 \pi {r}^{} = 132cm$

Volume of a Cylinder:

$\pi {r}^{2} h$

We need to find radius of the circle, using

$2\pi {r} \: = 132cm \\ 2 \times \frac{22}{7} \times r = 132cm \\ \frac{44}{7} \times r = 132cm \\ r = 132 \times \frac{7}{44} \\ r = 21cm$

Now we have radius = 21cm, and height = 25cm.

Therefore,

Volume of the cylindrical vessel :

$= \pi {r}^{2} h \\ = \frac{22}{7} \times {21}^{2} \times 25 \\ = \frac{22}{7} \times 21 \times 21 \times 25 \\ = 22 \times 3 \times 21 \times 25 \\ = 66 \times 21 \times 25 \\ = 34650 {cm}^{2}$

Therefore,

The volume of the cylindrical vessel is:

$34650 {cm}^{2}$