the circumference of the base of a right circular cone is 44 cm and its slant height is 10 cm. find the curved surface area
Answers
Answered by
30
↑ Here is your answer ↓
_____________________________________________________________
_____________________________________________________________
Given,
Circumference of the base,
'22' get cancelled out,
C.S.A of a right circular cone,
'7' is cancelled out,
So,
_____________________________________________________________
_____________________________________________________________
Given,
Circumference of the base,
'22' get cancelled out,
C.S.A of a right circular cone,
'7' is cancelled out,
So,
Answered by
6
heya dear,
here your amswer goes like this
Given,
Circumference of the base of the right circular cone = 44cm
circumference is nothing but boundary
so here the length of the boudary iz 44cm
》2 × (pi) × r = 44cm
》 2 × (22/7) × r = 44cm
》44/7 × r = 44
* by transposing (44/7) which is in LHS to RHS it will be (7/44) *
so now
r = 44 × 7/44
by canceling both numerator and denominatior
we get
r=7cm
curved surface area of cone (C.S.A) = r × pi × l
》7 × (22/7) × 10
*by canceling both numerator amd denominationr we get*
CSA =22×10
CSA =220sq.cm
i hope it helped you thanks
here your amswer goes like this
Given,
Circumference of the base of the right circular cone = 44cm
circumference is nothing but boundary
so here the length of the boudary iz 44cm
》2 × (pi) × r = 44cm
》 2 × (22/7) × r = 44cm
》44/7 × r = 44
* by transposing (44/7) which is in LHS to RHS it will be (7/44) *
so now
r = 44 × 7/44
by canceling both numerator and denominatior
we get
r=7cm
curved surface area of cone (C.S.A) = r × pi × l
》7 × (22/7) × 10
*by canceling both numerator amd denominationr we get*
CSA =22×10
CSA =220sq.cm
i hope it helped you thanks
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