Question

The circumference of the base of a right circular cylinder is 308 CM its height is 40 cm and the curved surface area of the cylinder

Answer 1

Circumference  = 2×π×r =308 cm

                 h  = 40 cm

             ∴ CSA = 2πr×h

                          =308×40

                          =12320cm²

                 

Answer 2

The curved surface area of the cylinder is 12320 sq.cm.

Step-by-step explanation:

Circumference of base = $2\pi r$

We are given that The circumference of the base of a right circular cylinder is 308 CM

$2\pi r = 308$

$2 \times \frac{22}{7} \times r = 308$

$r = 308 \times \frac{7}{22 \times 2 }$

$r = 49$

Height of cylinder = 40 cm

Curved surface area of cylinder = $2 \pi rh = 2 \times \frac{22}{7} \times 40 \times 49 = 12320 cm^2$

Hence  the curved surface area of the cylinder is 12320 sq.cm.

#Learn more:

Radius and height of a cylinder is 7 cm. Find curved surface area of the cylinder

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