Question

the circumference of the base of conical tent is 44metre and height is 15metre .how much Canvas is required for tent ? find also the volume of air occupied in the tent ?
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Answer 1

★$\huge\bf{\blue{\underline{Question:-}}}$

the circumference of the base of conical tent is 44metre and height is 15metre .how much Canvas is required for tent ? find also the volume of air occupied in the tent ?

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★$\huge\bf{\green{\underline{Explanation:-}}}$

$for \: the \: conical \: tent - \\ height = 24 {cm}^{2} \\ circumference = 44 {cm}^{2} \\ 2\pi \: r = 44 \\ 2 \times \frac{22}{7} \times r = 44 \\ r = 44 \times \frac{7}{22} \times \frac{1}{2} \\ r = 7cm \\ curved \: surface \: area = rl\pi \\ {l}^{2} = \ {r}^{2} + {h}^{2} \\ {l}^{2} = {24}^{2} + {7}^{2} \\ {l}^{2} = 25cm \\ curved \: surface \: area = \frac{22}{7} \times 7 \times 25 \\ curved \: surface \: area = 550 {cm}^{2} \\ area \: of \: the \: canvas = curved \: srurface \: area \\ lr\pi = l \times b \\ 550 {cm}^{2} = \: l\times b \\ 550 = l\times 2 \\ l = 550 \div 2 \\ l = 275cm \\ therefore \: length \: of \: the \: canvas = 275cm$

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Answer 2

Answer:

Let the radius of the base be r meters Then

2

πr

= 44

or

r=

2π

44

=

2 × 2 2

4 4 × 7

=

7m

Let the slant height be l meters Then

l=

2

h 2

=

2

7 2

=

625

=

25m

Now, Surface area =

πrl=

7

22

×

7×

25=

550m

2

∴

Area of canvas required

=

550

m

2

Given that width of the canvas is

2

m therefore

Length of canvas required =

2

550

=

275m