The circumference of the base of cylindrical vessel is 440cm and its height is 80 cm, find the volume of the cylinder in m^3
Answers
Answered by
3
Step-by-step explanation:
circumference = 2πr = 88 (given)
so, 2× π × r = 88
π×r = 88 / 2
22/7 × r = 44
r= (44×7) / 22
r= 2×7
r= 14cm
Volume= πr²h
=(22/7) × 14×14 × 60 (h=60)
=44×14×60
=36960 cm³
C.S.A. = 2πrh
= 2× [22/7] ×14 × 60
=88×60 (2πr = 88 [given])
=5280 cm²
Answered by
6
Answer:
1232m³
Step-by-step explanation:
Base of the cylindrical vessel = 440cm
Height = 80cm
Circumference of the base = 2πr
440 = 2×22/7×r
= 440×7/2×22
= 10×7 = 70
Volume of the cylinder= πr²h
∴ 22/7×70×70×80
= 22×10×70×80
=1232m³
There will be more 0s in the answer but we will just write 1232.
Thank you.
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