Math, asked by rajumall714, 7 months ago

The circumference of the base of cylindrical vessel is 440cm and its height is 80 cm, find the volume of the cylinder in m^3​

Answers

Answered by kulkarninishant346
3

Step-by-step explanation:

circumference = 2πr = 88 (given)

so, 2× π × r = 88

π×r = 88 / 2

22/7 × r = 44

r= (44×7) / 22

r= 2×7

r= 14cm

Volume= πr²h

=(22/7) × 14×14 × 60 (h=60)

=44×14×60

=36960 cm³

C.S.A. = 2πrh

= 2× [22/7] ×14 × 60

=88×60 (2πr = 88 [given])

=5280 cm²

Answered by jimmy200bhatt
6

Answer:

1232m³

Step-by-step explanation:

Base of the cylindrical vessel = 440cm

Height = 80cm

Circumference of the base = 2πr

440 = 2×22/7×r

= 440×7/2×22

= 10×7 = 70

Volume of the cylinder= πr²h

∴ 22/7×70×70×80

= 22×10×70×80

=1232m³

There will be more 0s in the answer but we will just write 1232.

Thank you.

Similar questions