Question

the circumference of the circular base of a cylindrical pillar is 33 ft. and it's height is 10 ft. the top of the pillar has a combined cone of height 7 ft. find the cost of painting the combined structure of the pillar at the rate of rs 40 per sq. ft.​

Answer 1

Answer:

Given radius of cylinder =

2

D

=

2

50

=25 cm=0.25 m

Height of cylinder =3.5 m

CSA of cylinder = 2πrh

=2π(0.25×3.5)

CSA of cylinder =5.5 m

2

cost of painting per meter square =12.50 RS

Total cost of painting =12.50×5.5=68.75 RS.

Answer 2

Step-by-step explanation:

• circumference of the circular base =2pie r sq.=33 now, 2×22÷7r= 33. r= 33 ×7÷44=5.25. again, L square =H square +R square .L square = 7×7+ 5.25 × 5.25 =76.5625. L square =76.5625. LSquare =underroot 76.5625=8.75. again c.s.a of cylinder =2pie r h= 330 cm. c.s.a of cone =pie r l = 144.375 cm. lly,the cost of painting the combined structure of the piller at the rate of 40per sq.ft = 330 + 144.375 ×40=18975