The circumference of the cross section of a hemispherical bowl is 132cm. Find the capacity of the bowl ( Take pie= 22/7)
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3
circumference of cross section=132cm^2
2πr=132
r=132/2π
r=3×7
r=21cm
capacity=volume
2/3πr^3
2/3×22/7×21×21×21
=2×22×21×21
=44×441
19371cm^3 will be the capacity of hemispherical bowl..
2πr=132
r=132/2π
r=3×7
r=21cm
capacity=volume
2/3πr^3
2/3×22/7×21×21×21
=2×22×21×21
=44×441
19371cm^3 will be the capacity of hemispherical bowl..
Answered by
2
Answer:
circumference=132 cm
2πr = 132 cm
2 × 22/7× r = 132
44/7 x r = 132
r= 132 x 7/44
r = 21
volume of hemisphere = 2/3 πr³
=2/3 x 22/7 x 21x21x21
=44x 441
=19404 cm³
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