Math, asked by rahilfarooqui786, 8 months ago

THE CIRCUMFERENCE OF THE FRONT WHEEL OF A CAR IS 10 DM AND THAT OF THE HIND WHEEL IN 16 DM HOW MANY REVOLUTION MORE WILL THE FIRST WHEEL MAKE THAN THE SECOND IN COVERING A DISTANVE OF 96 KM​

Answers

Answered by rohitpranshu2006
10

Answer:

36000

Step-by-step explanation:

D = 96 km

= 96000 m

Front wheel = hind wheel

C = 10 dm

= 1 m

No. Of rotation = diameter/circumference

= 96000

No. Of revolution = d/circumference

= 60000

Difference = 96000 - 60000

= 36000

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