the circumference of the front wheel of a car is 10 DM and that of the Hind wheel is 16 dm how may revolution more will the first wheel make then the second in covering a distance of 96 km?
Answers
Answered by
87
hey sis here is your answer
If Dm = decimeter ; 1. circumference 10 Dm = 1 meter so revolution distance = 96000 meter .
so front wheel takes 96000 revolution.
2. similarly 1dm = 1/ 10 meter so 16 Dm = 16/ 10 = 1.6 meter of circumference .
Rear wheel revolution = 96000/ 1.6 = 60000
so answer is 96000-60000= 36000 more revoption by front or first wheel
hope it helps you
If Dm = decimeter ; 1. circumference 10 Dm = 1 meter so revolution distance = 96000 meter .
so front wheel takes 96000 revolution.
2. similarly 1dm = 1/ 10 meter so 16 Dm = 16/ 10 = 1.6 meter of circumference .
Rear wheel revolution = 96000/ 1.6 = 60000
so answer is 96000-60000= 36000 more revoption by front or first wheel
hope it helps you
ishu2767:
Bro thanks but i am not girls i am a boy
Answered by
144
The circumference of the front wheel of a car is 10dm.
Circumference of the hind wheel is 1dm.
1dm = 1/10m
16dm = 16/10m
= 1.6m
10dm = 10/10m
= 1m
1km = 1000m
96km = 96000m
First wheel revolution = 96000/1.6m
= 60000m
Second wheel revolution = 96000/1m
= 96000m
More revolution the first wheel will make = 96000 - 60000
= 36000 revolution
Circumference of the hind wheel is 1dm.
1dm = 1/10m
16dm = 16/10m
= 1.6m
10dm = 10/10m
= 1m
1km = 1000m
96km = 96000m
First wheel revolution = 96000/1.6m
= 60000m
Second wheel revolution = 96000/1m
= 96000m
More revolution the first wheel will make = 96000 - 60000
= 36000 revolution
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