The circumference of the front wheel of a car is 10dm and that of the hind wheel in 16dm. How may revolutions more will the first wheel make than the second in covering a distance of 96km?
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We know that,
1 km = 10000 dm
Now, 96 km = 960000 dm
FOR FRONT WHEEL :
Circumference of front wheel = 10 dm
Number of revolutions taken to cover 10 dm = 1
So, number of revolutions taken to cover 960000 dm = 960000/10 = 96000
FOR HIND WHEEL :
Circumference of hind wheel = 16 dm
Number of revolutions taken to cover 16 dm = 1
So, number of revolutions taken to cover 960000 dm = 960000/16 = 6000
Number of extra revolutions made by hind wheel than front wheel = 96000 - 6000 = 36000
1 km = 10000 dm
Now, 96 km = 960000 dm
FOR FRONT WHEEL :
Circumference of front wheel = 10 dm
Number of revolutions taken to cover 10 dm = 1
So, number of revolutions taken to cover 960000 dm = 960000/10 = 96000
FOR HIND WHEEL :
Circumference of hind wheel = 16 dm
Number of revolutions taken to cover 16 dm = 1
So, number of revolutions taken to cover 960000 dm = 960000/16 = 6000
Number of extra revolutions made by hind wheel than front wheel = 96000 - 6000 = 36000
shreeya81:
how many revolutions
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