The circumference of the front wheel of a cart is 3 m long and that of the back wheel is 4 m long. What is the distance travelled by the cart, when the front wheel makes five more revolutions than the rear
wheel?
Answers
Answered by
49
Let the total distance travelled by the cart be ‘x’ metres Number of revolutions = (Distance travelled)/(Circumference) Number of revolutions made by front wheel = x/3 Number of revolutions made by rear wheel = x/4
x/3-x/4 =5
4x-3x/12=5
x/12=5
x=60
the total distance travelled by the cart is 60 metres.
x/3-x/4 =5
4x-3x/12=5
x/12=5
x=60
the total distance travelled by the cart is 60 metres.
Answered by
22
Answer:
60 m
Step-by-step explanation:
Distance traveled by front wheel in 1 revolution= circumference=3m
Distance traveled by rear wheel=circumference=4m
Let the distance traveled be x meter
So distance traveled by front wheel is x/3 meter
So distance traveled by rear wheel is x/4 metre
ATQ
Distance traveled by front wheel - distance traveled by rear wheel= distance traveled by the 5 extra revolutions taken by the front wheel
x/3-x/4. (LCM)
4x/12-3x/12
x/12 metres
Next, extra distance= extra revolutions
x/12=5
x= 5×12
x=60
So the total distance was 60 metres
( Same as the solution given in ncert examplar class 8)
Thx
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