Question

The circumference of the front wheel of a cart is 30 feet long. What is the distance travelled by
the cart, when the front wheel has done five more revolutions than the rear wheel?​

Answer 1

●Correct question:-

The circumference of the front wheel of a cart is 30 ft long and that of the back wheel is 36 ft long. What is the distance travelled by the cart, when the front wheel has done five more revolutions than the rear wheel? 

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▪Given that:-

• The circumference of the front wheel is 30 ft and that of the rear wheel is 36 feet.

▪To find:-

• Distance travelled by the cart.

●Solution:-

Let the rear wheel make n revolutions.

At this time, the front wheel should have made n+5 revolutions.

As both the wheels would have covered the same distance

$\implies$n*36 = (n+5)*30

$\implies$ 36n = 30n + 150

$\implies$ 6n = 150

$\implies$ n = 25.

Distance covered = 25 × 36 = 900 ft.

$\therefore$Distance travelled by cart is 900 ft.

Answer 2

Step-by-step explanation:

Let the rear wheel make n revolutions.

At this time, the front wheel should have made n+5 revolutions.

As both the wheels would have covered the same distance

\implies⟹ n*36 = (n+5)*30

\implies⟹ 36n = 30n + 150

\implies⟹ 6n = 150

\implies⟹ n = 25.

Distance covered = 25 × 36 = 900 ft.

\therefore∴ Distance travelled by cart is 900 ft.