The circumference of the orbit should be an integral multiple of the
of
the electron wave
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Answer:
The expression for the angular momentum is mvr=
2π
nh
, or 2πr=
mv
nh
......(i)
The wavelength is given by the De Broglie's equation.
λ=
mv
m
.....(ii)
From (i) and (ii), we have
2πr=nλ
Hence, the circumference of the Bohr orbit for the hydrogen atom is an integral multiple of the de Broglie's wavelength associated with the electron revolving around the orbit.
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