Chemistry, asked by jayasudhaganesh84, 6 months ago


The circumference of the orbit should be an integral multiple of the
of
the electron wave​

Answers

Answered by shubhamverma90
0

Answer:

The expression for the angular momentum is mvr=

nh

, or 2πr=

mv

nh

......(i)

The wavelength is given by the De Broglie's equation.

λ=

mv

m

.....(ii)

From (i) and (ii), we have

2πr=nλ

Hence, the circumference of the Bohr orbit for the hydrogen atom is an integral multiple of the de Broglie's wavelength associated with the electron revolving around the orbit.

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