the circumference of the wheels of a carriage a 3 M 25 cm and 5 M. Find the least distance in which both wheels make an exact number of revolutions. solve
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Answered by
31
the circumference of one wheel is 3m 25 cm and other is 5 m
let the 1st wheel make n+1.5 revoution and other wheel n
as boyh the wheels have to cover same distance
n*5=(1.5+n)3.5
solve it you will get
n=3.5
hope it will be the ans
let the 1st wheel make n+1.5 revoution and other wheel n
as boyh the wheels have to cover same distance
n*5=(1.5+n)3.5
solve it you will get
n=3.5
hope it will be the ans
Answered by
2
Answer:
Concept :
The whole distance encircling a circle's outside is known as its circumference. Circumference is equal to the circle's diameter multiplied by (pi), or approximately 3.14. A wheel can move a distance equal to its circumference in one revolution.
Explanation:
Given :
The circumference of the wheels of a carriage are 3m 25cm and 5m
To find :
Both wheels of revolutions
Solution :
Convert m to cm so,
325 cm and 500 cm.
L.C.M. of 325 and 500 are 2 × 2 × 5 × 5 × 5 × 13 = 6500
In metres,
= 6500/100
= 65m
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