the circumference of two circles are in the ratio 1:3 .find the ratio of their areas.
Answers
Answered by
21
let the radii of the two circles be R1 and R2
circumference of a circle = 2πr
therefore
2πR1/2πR2 = 1/3
R1/R2 = 1/3
therefore 3R1 = R2
ratio of areas:
area of a circle = πr²
therefore
πR1²/π(3R1)²
= R1²/9R1²
= 1/9
circumference of a circle = 2πr
therefore
2πR1/2πR2 = 1/3
R1/R2 = 1/3
therefore 3R1 = R2
ratio of areas:
area of a circle = πr²
therefore
πR1²/π(3R1)²
= R1²/9R1²
= 1/9
Answered by
4
Answer:
let the radii of the two circles be R1 and R2
circumference of a circle = 2πr
therefore
2πR1/2πR2 = 1/3
R1/R2 = 1/3
therefore 3R1 = R2
ratio of areas:
area of a circle = πr²
therefore
πR1²/π(3R1)²
= R1²/9R1²
= 1/9
HOPE IT HELPS!!!!!!!!!!
Similar questions