the circumference of two circles are in the ration 4:6 find the ratio of their areas
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Answered by
8
Answer :
The required ratio is 4 : 9
Step-by-step explanation :
Circumference of 1st circle / circumference of 2nd circle = 2 π r / 2 π r
⇒ 2 π R / 2 π r = 4 / 6
⇒ R / r = 4 / 6
⇒ R : r = 4 : 6
On squaring both sides,
⇒ R² : r² = 4² : 6²
⇒ R² : r² = 16 : 36
⇒ R² : r² = 4 : 9
Therefore, π R² : π r² = 4 : 9.
Answered by
5
Let the radii of the two circles be r and R respectively.
Then their circumferences will be 2πr and 2πR
Hence 2πr : 2πR = 4:6 so that r:R = 4:6
Squaring r^2:R^2 = 16:36
Ratio of their areas πr^2:πR^2 = r^2:R^2 = 16:36 ➡4: 9
hope that my answer will helpful for you
Then their circumferences will be 2πr and 2πR
Hence 2πr : 2πR = 4:6 so that r:R = 4:6
Squaring r^2:R^2 = 16:36
Ratio of their areas πr^2:πR^2 = r^2:R^2 = 16:36 ➡4: 9
hope that my answer will helpful for you
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