the circumfrence of the base a 12cm height wooden solid cone is 44m find the volume of cone and tsa
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2
circum = 2 pi r
44m = 2 * 22/7 *r
44m/2 = 22/7 *r
22m *7 /22 =r
r =7m
volume of cone = 1/3 pi r square h
= 1/3 x 22/7 x 7 x 7 x 12
= 88m cube
total surface area = pi r(l + r)
we need to find 'l' so we should use
l = root of ( r square + h square)
= root of ( 7 square + 12 squ)
= root of ( 7056)
l= 84 m
now we can apply tsa formula;
tsa = pi r (l + r)
= 22/7 * 7 (84 + 7)
= 1848 + 154
= 2002 m squ
hope this helps u pzzz mark as brainlist..
44m = 2 * 22/7 *r
44m/2 = 22/7 *r
22m *7 /22 =r
r =7m
volume of cone = 1/3 pi r square h
= 1/3 x 22/7 x 7 x 7 x 12
= 88m cube
total surface area = pi r(l + r)
we need to find 'l' so we should use
l = root of ( r square + h square)
= root of ( 7 square + 12 squ)
= root of ( 7056)
l= 84 m
now we can apply tsa formula;
tsa = pi r (l + r)
= 22/7 * 7 (84 + 7)
= 1848 + 154
= 2002 m squ
hope this helps u pzzz mark as brainlist..
Answered by
0
HERE IS YOUR ANSWER
I HOPE THIS HELPS YOU
l^2= 144+49
√193
TSA = πr(l+r)
=22/7×7(√193+7)
= 22×(√193+7)
I HOPE THIS HELPS YOU
l^2= 144+49
√193
TSA = πr(l+r)
=22/7×7(√193+7)
= 22×(√193+7)
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