Math, asked by Harper1234, 8 months ago

The circumradius of an equilateral triangle is 4 cm.Draw the triangle and measure its side​

Answers

Answered by suyashtilekar54
1

Step-by-step explanation:

Steps of construction:-

Draw a line segment BC=4cm

With B as centre and radius of 4cm, draw an arc.

Similarly, with C as centre and radius of 4cm, draw another arc to intersect the previous arc at A.

Join AB and AC.

ABC is the required equilateral triangle.

Draw the perpendicular bisector of the sides of the triangle.

Mark the point of intersection of the perpendicular bisectors as 'O' which is called the circumcentre of the triangle.

With 'O' as centre, OA or OB or OC as radius, draw a circle passing through A,B and C.

Hence the circumcircle of the equiateral triangle is constructed.

solution

Answered by sadiaanam
0

Answer:

Here is the required steps of construction to draw the triangle of the circumradius of an equilateral triangle is 4 cm.

Step-by-step explanation:

An equilateral triangle is one with equally long sides on both sides. The three angles opposite the three equal sides are equal in size because the three sides are equal. It is also known as an equiangular triangle since each angle is 60 degrees.

Steps of construction :

  • Step 1: Draw a line segment BC = 4cm.
  • Step 2: With centers B and C, draw two arcs of radius 4cm which intersects each other at point A.
  • Step 3: Join AB and AC.
  • Step 4: Draw the right bisector of BC and AC intersecting each other at point O.
  • Step 5: Join OA, OB and OC.
  • Step 6: With center as O, and radius equal to OB or OC or OA, draw a circle which passes through points A, B and C.

Hence the required circumcircle of triangle ABC is drawn.

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