Question

the circumstances of four wheels are 50 cm, 60 cm,75 cm and 100 cm. They start moving simultaneously, what least distance should they cover so that each wheel makes a complete number of revolutions​

Answer 1

Answer: Simple do L.C.M. of 50,60,75,100.

5 |50,60,75,100

3 |10,12,15,20

2 |10,4,5,20

2 |5,2,5,10

5 |5,1,5,5

|1,1,1,1. so least common multiple of these 4 numbers =5×3×2×2×5=300 . So distance travelled =2π(300)=600π=1884cm approximately

: thanks