Question

The class intervals for a continuous variable are 0-90,100-199,200-299,300-399, find the mid value of third class? (a) 149.5 (b)249.5 (c) 349.5 (d) 17.5​

Answer 1

Step-by-step explanation:

Let the lower limit be l and upper limit be u.

Then, u−l=4...(1)

and

2

u+l

=15 or u+l=30...(2)

Subtracting (2) and (1),

u+l−u+l=30−4

2l=26

l=13

Thus, lower limit =13

Answer 2

Answer:

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Step-by-step explanation:

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