Math, asked by subratanandy82, 1 year ago

The Class IX students of a certain public school wanted to give a farewell part
the outgoing students of Class X. They decided to purchase two kinds of sweets,
costing rupees 70 per kg and the other costing rupees 84 per kg. They estimated that 36 kg of sweets were needed. If the total money spent on sweets was 2800, find how n
sweets of each kind they purchased.​

Answers

Answered by pallu723
11

¶¶helo¶¶thank you dear for asking questions and plz don't delete the answer because I am not copy to google.ok

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Answered by aktshayaa7a20192020
0

Answer:

84

Step-by-step explanation:

Let the quantity of sweet costing Rs 70 be x

And, the quantity of sweet costing Rs 84 be y

Given, total quantity of sweets purchased is 34 kg

x + y = 34 … (i)

Also given, the total money spent is Rs 2800

70x + 84y = 2800 … (ii)

Multiplying (i) by 70 and subtracting with (ii), we get

70x + 70y = 2520

70x + 84y = 2800

(-)—(-)—–(-)——

-14y = -280

y = -280/-14

y = 20

On substituting the value of y in equation (i), we get

x + 20 = 36

x = 36 – 20

x = 16

Therefore, the quantities of sweets purchased are 16 kg which costs Rs 70 per kg and 20 kg which costs Rs 84 per kg.

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