Question

The class mark of a class interval is 30. If the class size is 10, find the upper limit and the lower limit of the class. don't c0py :)​

Answer 1

Answer:

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Given, Class mark of a class interval (a) = 30.

Given, Class size (h) = 10.

Lower limit = a - h/2.

= 30 - (10/2)

= 30 - 5

=25.

Upper limit= a + (h/2).

= 30 + (10/2)

= 30 + 5

= 35.

Upper limit= 25

Lower limit= 35.

Step-by-step explanation:

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Answer 2

Answer:

25,35

Step-by-step explanation:

given,class mark of a class interval (a)=30

lower limit=a-h/2

=30-(10/2)

=30-5

=30-5 =25

=30-5 =25upper limit =a+(h/2)

=30-5 =25upper limit =a+(h/2) =30+10/2

=30-5 =25upper limit =a+(h/2) =30+10/2 =30+5

=30-5 =25upper limit =a+(h/2) =30+10/2 =30+5 =35

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