the class marks of a distribution are 11,15,19,23, 27,31,35 determine the class size and class boundaries
Answers
Here,
Class size = Difference b/w any two consecutive class marks = 31-26 = 5
Therefore,
Lower limit of first class interval = 26−
2
5
=23.5
Upper limit of first class interval = 26+
2
5
=28.5
Therefore, first class interval is 23.5-28.5.
Thus, the class intervals are :
23.5−28.5,28.5−33.5,33.5−38.5,38.5−43.5,43.5−48.5,48.5−53.5
Since, the classes are formed by exclusive method. Therefore, these limits are true class limits.
I hope this will help you please add me to brainlist plzz and follow me
Answer:
Here,
Class size = Difference b/w any two consecutive class marks = 31-26 = 5
Therefore,
Lower limit of first class interval = 26− 2 .5 =23.5
Upper limit of first class interval = 26+ 2 .5 =28.5
Therefore, first class interval is 23.5-28.5.
Thus, the class intervals are :
23.5−28.5
28.5−33.5
33.5−38.5
38.5−43.5
43.5−48.5
48.5−53.5
Since, the classes are formed by exclusive method. Therefore, these limits are true class limits.