The class marks of a distribution are 26,31,36,41,46,51,56,61,66,71. Find
the true class limits.
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Here,
Class size = Difference b/w any two consecutive class marks = 31-26 = 5
Therefore,
Lower limit of first class interval = 26−
2
5
=23.5
Upper limit of first class interval = 26+
2
5
=28.5
Therefore, first class interval is 23.5-28.5.
Thus, the class intervals are :
23.5−28.5,28.5−33.5,33.5−38.5,38.5−43.5,43.5−48.5,48.5−53.5
Since, the classes are formed by exclusive method. Therefore, these limits are true class limits.
Class size = Difference b/w any two consecutive class marks = 31-26 = 5
Therefore,
Lower limit of first class interval = 26−
2
5
=23.5
Upper limit of first class interval = 26+
2
5
=28.5
Therefore, first class interval is 23.5-28.5.
Thus, the class intervals are :
23.5−28.5,28.5−33.5,33.5−38.5,38.5−43.5,43.5−48.5,48.5−53.5
Since, the classes are formed by exclusive method. Therefore, these limits are true class limits.
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