the class marks of a frequency distribution are 104 114 124 134 14 4 154 and 164 find the class size and class intervals
Answers
Answered by
13
Since the class marks are equally spaced.
∴ Class size = 114 – 104 = 10
If a is a class mark and h is size of class interval, then lower limit and upper limit of the class
interval area a - h / 2 and a + h / 2 respectively.
∴ we have h = 10
∴ Lower limit of first class interval = 104 - 10 / 2 = 99
Upper limit of first class interval = 104 + 10 / 2 = 109
∴ First class interval is 99 - 109
Hence, the class intervals are 99 - 109, 109 - 119, 119 - 129, 129 - 139, 139 - 149, 149 - 159, 159 - 169.
∴ Class size = 114 – 104 = 10
If a is a class mark and h is size of class interval, then lower limit and upper limit of the class
interval area a - h / 2 and a + h / 2 respectively.
∴ we have h = 10
∴ Lower limit of first class interval = 104 - 10 / 2 = 99
Upper limit of first class interval = 104 + 10 / 2 = 109
∴ First class interval is 99 - 109
Hence, the class intervals are 99 - 109, 109 - 119, 119 - 129, 129 - 139, 139 - 149, 149 - 159, 159 - 169.
Answered by
0
Answer:
sorry I don't know the answer
Similar questions