Question

The class marks of distribution are 61, 66, 71, 76, 81, 86, 91, 96, 101, 106 Determine the class size, class limits. and true class limits.​

Answer 1

Answer:

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Since class marks (mid values) are uniformly spaced, so the class-size is the differnce between any two consecutive class marks. Therefore, class size = 66-61 = 5

Let the lower limit of the first class be a. ∴ Its upper limit = a + 5

∴Its upper limit=a+5 Its mid value = 61

∴ Class mark = upper limit + lower limit 2

∴ Class mark=upper limit + lower limit2

⇒ a + ( a + 5 )/2 = 61

⇒ a + ( a + 5 ) = 122

⇒ 2 a + 5 = 122

⇒ 2 a = 117

⇒ a = 58.5

for class interval

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