The class marks of the given frequency distribution are 19.5,26.5,33.5 and 40.5.Write the corresponding class intervals.
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Step-by-step explanation:
Solution
Class mark is the mid point of the class interval.
Class size is the upper limit minus lower limit.
Given that class mark of a class is
6.5
and
the class size is
26.5
−
19.5
=
33.5
−
26.5
=
40.5
−
33.5
=
7
By option verification,
Opition A class mark is
16
+
23
2
=
39
2
=
19.5
False
Option B class mark is
30
+
23
2
=
53
2
=
26.5
False
Option C class mark is
30
+
37
2
=
67
2
=
33.5
and
class size is
37
−
30
=
7
True
Option D class mark is
37
+
41
2
=
78
2
=
39
False
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