the classroom door is of 50 cm if the handle of door is 20 cm from the edge and the force of 2 newton is applied on the other find the torque
Answers
Answer:
The Classroom door is of width 50 cm. If the Handle of the door is 20 cm from the edge and Force of 5N is applied on the handle. Calculate the torque? I have attached what I think is the answer. But the answer on the site from where I took this question is 0.8 Nm. Here is the answer the site gives:- Handle of the door is situated at 20 cm. Therefore line of action is 20/2 = 10 cm. Length of the lever arm = d = 50 - 10 = 40 cm = 0.4 m Force applied = 2N Torque = F × d = 2N × 0.4 m = 0.8 Nm.
Answer:
The torque is 0.8 Nm.
Explanation:
Step 1: A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to define force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Step 2: The force that may cause an item to revolve along an axis is measured as torque. Similar to how force accelerates an item in linear kinematics, torque accelerates an object in an angular direction. A vector quantity is a torque.
Step 3: The Classroom door is of width 50 cm. If the Handle of the door is 20 cm from the edge and Force of 5N is applied on the handle. Calculate the torque? I have attached what I think is the answer. But the answer on the site from where I took this question is 0.8 Nm. Here is the answer the site gives:- Handle of the door is situated at 20 cm. Therefore line of action is 20/2 = 10 cm. Length of the lever arm = d = 50 - 10 = 40 cm = 0.4 m Force applied = 2N Torque = F × d = 2N × 0.4 m = 0.8 Nm.
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