Question

The classroom door is width 50 cm , if the handle of the door is 20 cm from the edge and force of 2N is applied on the handle? Find the torque?​

Answer 1

Answer: 0.8 Nm.

Step-by-step explanation:

Handle of the door is situated at 20 cm. Therefore line of action is 20/2 = 10 cm. Length of the lever arm = d = 50 - 10 = 40 cm = 0.4 m Force applied = 2N Torque = F × d = 2N × 0.4 m = 0.8 Nm.

Answer 2

Answer:

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Step-by-step explanation:

• Here is the answer the site gives:- Handle of the door is situated at 20 cm. Therefore line of action is 20/2 = 10 cm. Length of the lever arm = d = 50 - 10 = 40 cm = 0.4 m Force applied = 2N Torque = F × d = 2N × 0.4 m = 0.8 Nm.

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