Question

the cliff and the person
= 1730 m/2 = 865 m.
uestion
1. An echo returned in 3 s. What is
the distance of the reflecting
surface from the source, given
that the speed of sound is
342 m s-l?​

Answer 1

Answer:

Given time (t) = 3 s & speed of sound (v) = 342 ms^-1, distance (d) = ?

$speed \: of \: sound \: = \frac{distance}{time}$

$v = \frac{d}{t}$

$342 = \frac{d}{3}$

$d = 342 \times 3$

$d = 1026 \: m$