the co ordinate of Q is 2 and the co ordinate of T is 5 find d (QT)
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Answer:SP=
(at
2
−a)
2
+(2at−0)
2
=a
(t
2
−1)
2
+4t
2
=a(t
2
+1)
and, SQ=
(
t
2
a
−a)
2
+(
t
2a
−0)
2
⇒SQ=
t
4
a
2
(1−t
2
)
2
+
t
2
4a
2
⇒SQ=
t
2
a
(1−t
2
)
2
+4t
2
=
t
2
a
(1+t
2
)
2
=
t
2
a
(1+t
2
)
∴
SP
1
+
SQ
1
=
a(t
2
+1)
1
+
a(t
2
+1)
t
2
⇒
SP
1
+
SQ
1
=
a(t
2
+1)
1+t
2
=
a
1
,
Step-by-step explanation:
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