Question

The co-ordinates of a focus of the ellipse 4x +9y2 = 1, is
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Answer 1

Answer:

(±√5,0)

Step-by-step explanation:

4x² + 9y² = 1                        

or, x²/1/4 + y²/1/9 = 1  

hence , a² = 1/4              ; a = 1/2                      ∴e = √(1- b²/a²) = √( 1 - 4/9 )

             b² = 1/9             ; a = 1/3                                                = √5 / 3

hence the coordinates of the focus is = (±ae, 0)  

                                                               = (±3×√5/3,0) = (±√5,0)