Question

The co-ordinates of angular point of a triangle
ABC are Alo, 1), B12, 0) and C-1,-2). Find the
equation of side AB of the triangle.​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The equation of sides AB is 2y+x = 2, BC is 3y =2x-4, AC is y = 3x+1

Step-by-step explanation:

Given :

Coordinates of angular points are (0,1), (2,0), (-1,-2)

$\text{Slope (m)} = \frac{\text{y}_2 - \text{y}_1}{\text{x}_2 - \text{x}_1}$

Lets take side AB with angular points (0,1) and (2,0)

 $\text{m} = \frac{0-1}{2-0} = \frac{-1}{2}$

$\text{Point slope formula is} \ \text{y}-\text{y}_1=\text{m(x}-\text{x}1)$

Substitute the formula for 'm' in the above equation                  

 $\text{y}-\text{y}_1= \frac{\text{y}_2 - \text{y}_1}{\text{x}_2 - \text{x}_1} \text{(x}-\text{x}1)$                                    

 $\text{y}-1 = \frac{-1}{2} (\text{x}-0)$

$\text{y}-1 = \frac{-1}{2} \ \text{x}$

2 y- 2 = - x

2y+x=2 is the equation of side AB.

Lets take side BC with angular points (2,0) (-1,-2)

$\text{m} = \frac{-2-0}{-1-2} = \frac{2}{3}$

Substituting m value in point slop formula we get,

 $\text{y}-0=\frac{2}{3} (\text{x}-2)$

3y=2x-4 is the equation of side BC.

Similarly the equation for the side AC is y = 3x+1.

To Learn More....

1.  P.Q.R have coordinates (-2, 1), (2.2) and (6.-2)  respectively. Write down

1- the gradient of OR:  2- the equation of the line through P perpendicular

to qr

brainly.in/question/10959419

2.The areas of two similar triangle ABC and PQR are in the ratio 9:16.if BC=4.5cm, find the length of QR.

brainly.in/question/1435271