The co-ordinates of centre of mass ofparticles of mass 30, 10 and 20 gm are (2,2,2)cm.1 position co-ordinatesof mass 40 gm which when added tothe system, the position of combinedcentre of mass be at (0, 0, 0) are.
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Answer:
Correct option is
B
−
2
3
,−
2
3
,−
2
3
initialy:inxdirection
x
cm
=
60
10(x
1
)+20(x
2
)+30(x
3
)
=1
⇒10(x
1
)+20(x
2
)+30(x
3
)=60
finally:inxdirection
x
cm
=
100
10(x
1
)+20(x
2
)+30(x
3
)
=0
⇒60+40(x
4
)=0
⇒x
4
=
4
−6
=
2
−3
similarlyy
4
=
2
−3
z
4
=
2
−3
∴(
2
−3
,
2
−3
,
2
−3
)shouldbepositionof40gm
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