Question

The co-ordinates of one end of a diameter of a circle are (5,6) and the coordinates of
the centre of the circle are (3, -2). Find the coordinates of the other end of the
diameter

Answer 1

Answer:

(1, -10)

Step-by-step explanation:

one end of diameter = (5, 6)

let the other end be = (x2, y2)

center of circle = (3, -2)

midpoint formula

(x1 + x2)/2 , (y1 + y2)/2 = (x, y)

$\frac{x1 + x2}{2} = 3 \\ \frac{5 + x2}{2} = 3 \\ 5 + x2 = 3 \times 2 \\ 5 + x2 = 6 \\ x2 = 6 - 5 \\ x2 = 1 \\ \\ \frac{y1 + y2}{2} = - 2 \\ \frac{6 + y2}{2} = - 2 \\ 6 + y2 = - 2 \times 2 \\ 6 + y2 = - 4 \\ y2 = - 4 - 6 \\ y2 = - 10$

the other end of diameter = (1, -10)

Hope you get your answer