The co-ordinates of point B is 2 and that
of Point t is s. find a CB, E)
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Explanation:
Given, the points A(5,2),B(3,4) and C(x,y) are collinear i.e., A−B−Cand AB=BC
∴ B is the mid-point of AC.
By section formula,
(
2
x+5
,
2
y+2
)=(3,4)
⟹
2
x+5
=3 and
2
y+2
=4
⟹x+5=6 and y+2=8
⟹x=1 and y=6
Hence, the coordinates of C are (1,6).
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