Question

The co-ordinates of the mid point of the line segments joining the points A(2,3)and B(4,7)is

Answer 1

Given: Points A(2, 3) and B(4, 7).

To find: The mid - point of the line segment so formed by joining the points.

Answer:

Formula to find the formula:

$\tt P(x, y)\ =\ \bigg(\dfrac{x_1\ +\ x_2}{2},\ \dfrac{y_1\ +\ y_2}{2}\bigg)$

From the given data, we have:

$\tt x_1\ =\ 2\\\\x_2\ =\ 4\\\\y_1\ =\ 3\\\\y_2\ =\ 7$

Using them in the formula,

$\tt P(x, y)\ =\ \bigg(\dfrac{2\ +\ 4}{2},\ \dfrac{3\ +\ 7}{2}\bigg)\\\\\\P(x, y)\ =\ \bigg(\dfrac{6}{2},\ \dfrac{10}{2}\bigg)\\\\\\P(x, y)\ =\ \bigg(3,\ 5\bigg)$

Therefore, the coordinates of the mid - point joining the line segment formed by A(2, 3) and B(4, 7) is P(3, 5).

Answer 2

$\huge\bold\green{Question}$

The co-ordinates of the mid point of the line segments joining the points A(2,3)and B(4,7)is

$\huge\bold\green{AnsWer}$

According to the question we have

→ A(2, 3)

→ B(4, 7)

Now , we have to find the mid - point of the line segment so formed by joining the points.

Simply by using this formula we get :-

$\sf= P(x, y)\ =\sf{\dfrac{X_1\ +\ X_2}{2},\ \dfrac{Y_1\ +\ Y_2}{2}}$

Now by substituting the known values:-

$\begin{lgathered}\sf X_1\ =\ 2\\\\X_2\ =\ 4\\\\Y_1\ =\ 3\\\\Y_2\ =\ 7\end{lgathered}$

Using them in the formula,

$\begin{lgathered}\sf= P(x, y)\ =\ \bigg(\dfrac{2\ +\ 4}{2},\ \dfrac{3\ +\ 7}{2}\bigg)\\\\\\P(x, y)\ =\ \bigg\cancel(\dfrac{6}{2},\ \dfrac{10}{2}\bigg)\\\\\\P(x, y)\ =\ \bigg(3,\ 5\bigg)\end{lgathered}$

Hence , the required point is P(3, 5)