Math, asked by sonalhitenjain, 19 days ago

The co-ordinates of the point P dividing the line segment joining the points A(3,3) and B (6,6) internally in the ratio 2:1 are​

Answers

Answered by HeavenlySmells
10

Please refer to the attachment

Question

The co-ordinates of the point P dividing the line segment joining the points A(3,3) and B (6,6) internally in the ratio 2:1 are ___ .

  \bullet\sf \:Answer

The required coordinates of P = (5,5)

Solution

We know that in order to find the co-ordinates of P we have to apply Section Formula .

Let the co-ordinates of P be ( x , y )

Then , according to Section Formula

 \boxed{ \sf (x , y) =  (\dfrac{m_1 x_2 + m_2x_1}{m_1 + m_2}  \:  ,    \: \dfrac{m_1y_2 + m_2y_1}{m_1 + m_2})}

Here in the above formula

On Implementing the above values in section formula we'll get

 \sf(x,y) = ( \frac{2 \times 6 + 1 \times 3}{2 + 1}  \ ,\:  \frac{2 \times 6 + 1 \times 3}{2 + 1} )

 \boxed{ \sf(x,y) = ( \frac{12+ 3}{3}  \ ,\:  \frac{12+  3}{3} )}

 { \sf(x,y) = (   \frac{15}{3}  ,\frac{15}{3} )} =  \bf(5,5)

So , I must conclude that abscissa as well as ordinate of point P is 5

Thankyou

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