Question

the Co ordination of head and tail of a vector are, (2, 1,0) and(-4,2,-3).the magnitude of the vector is

Answer 1

magnitude will be√x^2+y^2+z^2

x = 2-(-4) = 6
y = 1-(2) = -1
z = 0-(-3) = 3

so
$\sqrt{ {6 }^{2} + ( { - 1}^{2}) + {3}^{2} }$



$\sqrt{36 + 1 + 9}$
$\sqrt{46}$