Question

the coace of a cricket team buys 7 bats and 6 balls for RS. 13200 . later he buys 3 bats and 5 balls for RS. 5900. find the cost of each bat each baiis.

Answer 1

Answer:

Rs. 1800 and Rs. 100

Step-by-step explanation:

Let x be the bats and y be the balls.

7x + 6y = 13200 => x = 13200 - 6y/7

3x + 5y = 5900

3(13200 - 6y/7) + 5y = 5900

[39600 - 18y/7] + 5y = 5900

39600 - 18y + 35y =  41300

17y = 41300 - 39600 = 1700

y = Rs. 100

x = Rs. 1800.

Answer 2

Step-by-step explanation:

Given :-

The coach of a cricket team buys 7 bats and 6 balls for 13200. Later he buys 3 bats and 5 balls for 5900

To Find :-

Cost of one bat and ball

Solution :-

Let

Price of bat = x

Price of ball = y

Now

7 × x + 6 × y = 13200

7x + 6y = 13200

Multiply by 5

5(7x + 6y) = 5(13200)

35x + 30y = 66000(1)

Now

3 × x + 5 × y = 5900

3x + 5y = 5900

Multiply by 6

6(3x + 5y) = 6(5900)

18x + 30y = 35400

Subtracting them

(35x + 30y) - (18x + 30y) = 66000 - 35400

35x + 30y - 18x - 30y = 30600

35x - 18x = 30600

17x = 30600

x = 30600/17

x = 1800

By putting in 1

35(1800) + 30y = 66000

63000 + 30y = 66000

30y = 66000 - 63000

30y = 3000

y = 3000/30

y = 100

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