Question

the coach of a cricket team buys 3 bats and 6 balls for rupees 3900 he buys another bat and 3 more balls of the same kind for rupees 1300 represent the situation algebraically​

Answer 1

Answer:

1300

Step-by-step explanation:

Answer

Reffer imagr.

let rate of bat = xRs.

and rate of ball = yRs.

3x+6y=3900.....(i)

and x+3y=1300.....(ii)

or x=(1300−3y)

now equation (i) can be written as

3(1300−3y)+6y=3900

3900−9y+6y=3900

∴y=0

Ans:- x=1300

solution

Answer 2

Step-by-step explanation:

Let the cost of one bat be Rs x

let cost of one ball be Rs y

given that,

3bats 6 balls cost Rs 3900

3x cost of bat+6x cost of one Ball- 3900

3x+6y=3900

3(x+2y)=3×1300

x+2y=1300

Also,

she buys another bat and 3 more balls of the same kind for Rs 1300

1xcost of one bat+3×cost of one ball=1300

x +3y=1300

NOW, plotting equation

x+2y=1300

x+3y=1300

Thanks