The coach of a cricket team buys 3 bats and 6 balls for ` 3900. Later, she buys another bat and 3 more balls of the same
kind for ` 1300. Represent this situation algebraically and geometrically.
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19
Answer:
cost of bat=X
cost of ball=y
3x+6y=3900
X+2y=1300
from equation (I)
3x + 6y=3900
X=3900-6y/3
X=1300 1100. 300
y=0. 100. 500
again from equation ii
X+2y=1300
X=1300-2y
X= 1300. 900. 300
y=0. 200. 500
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