Question

The coach of a cricket team buys 3 bats and 6 balls for ₹ 3900. Later, she buys another bat and 3 more balls of the same kind for ₹1300. Represent this situation algebraically and geometrically.​

Answer 1

Answer:

Let rate of bat = xRs.

and rate of ball = yRs.

3x+6y=3900

and x+3y=1300

or x=(1300−3y)

now equation (i) can be written as

3(1300−3y)+6y=3900

3900−9y+6y=3900

∴y=0

x=1300

Answer 2

Answer:

Refer to attachment :)

Step-by-step explanation:

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