The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys another bat and 3 more balls of the same kind for Rs 1300. Represent this situation algebraically and geometrically.
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Let the cost of a bat be Rs. x and cost of a ball be Rs. y.
Then algebraically representation of the question
To represent it geometrically, we plot the two equations
x+3y=1300⇒y=
3
1300−x
x 100 1000 1300
y=
3
1300−x
400 100 0
x+2y=1300⇒y=
2
1300−x
x 100 500 1300
y=
2
1300−x
600 400 0
As we can see, the lines intersect at (1300,0) which is the solution for this question
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