Question

The coach of a cricket team buys 3 bats and 6 balls for Rs.3900. Later, she buys another bat and 3 more balls of the same kind for Rs.1300. Represent this situation algebraically qqand geometrically

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Answer 1

Answer:

Given

first they bug 3 bats and 6 balls for Rs.3900

sencond time they buy 1 bat 3more ball for

RS.1300

•°•the total amount is =¥1300+3900

=¥5200

Explanation:

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Answer 2

Answer:

3x + y = 3900

x + 3y = 1300

Explanation:

Let x be the cost of 1 bat

Let y be the cost of 1 ball

Cost of 3 bats = 3x

Cost of 6 balls = 6y

Cost of 3 balls = 3y

The coach of a cricket team buys 3 bats and 6 balls for ₹ 3900

3x + 6y = 3900

She buys another bat and 3 more balls of the same kind for ₹1300.

x + 3y = 1300

So, situation algebraically :

3x + y = 3900

x + 3y = 1300