the coach of a cricket team buys 3 bats and 6 balls of the same kind for Rs.3900. later, she buys another bat and 3 more balls of the same kind for Rs.1300. Represent this situation algebraically and geometrically.
if any one know d answer pls answer it plsssss
Answers
Step-by-step explanation:
let cost of bat be Rs x
and cost of ball be rs y
According to question we have
3x +6y = 3900
x + 3y = 1300
Now we have to represent these lines of graph paper
Step by step explanation :
let the cost of one bat =x
let the cost of one ball=y
acc. to the question:-
3x + 6y = 3900 _ (I)eq
x + 3y = 1300_ (II) eq
from (I) eq
3x + 6y = 3900
3x + 6y -3900=0
3(x+2y-1300 ) = O
x+2y-1300=0 _ ( III ) equation
{fellow ones now see it clearly as we have the last number in hundreds so if we're going to substitute any value then we must take the value in hundreds .}
Now, Substituting the value of x= 100 in ( II )
equation:-
x + 3y = 1300
100+ 3y = 1300
3y = 1300-100
3y = 1200
y= 1200/3
y= 400
point = (100;400) on graph
Substituting the value of x = 400 in (II ) equation:-
x+ 3y = 1300
400+3y =1300
3y= 1300-400
3y= 900
y= 900/3
y=300
point= (400;300) on graph
{Note: you'll see these both points will intersect each other if they aren't then u might be wrong somewhere}
Now , Let us take (III ) equation
Substituting the value of x= 100 in ( III ) equation:-
x+ 2y -1300= O
x+ 2y = 1300
100+ 2y=1300
2y = 1300-100
2y= 1200
y= 1200/2
y= 600
point= (100;600) on graph
Substituting the value of x= 300 in (III ) equation :-
x+2y-1300=0
x+2y=1300
300+2y=1300
2y= 1300-300
2y= 1000
y= 1000/2
y= 500
point = (300;500) on graph
(you'll notice both the points of this equation will intersect each other on the graph)
so that's all
if u want the graph too then u can drop a msg for me
if u had question that why I put the values in just x then u can put urs value in y too
but I'll recommend to put values in x just because it's easy for u too understand
Thank you hope it helps