the coach of a cricket team buys 3hate and 6balls for3900/-. Later she buys another bat and 3more balls of the same kind for 1300/-. Represent this situation algebraically and geometrically
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let the cost of each bat =X
let the cost of each ball=Y
atq
3x +6y =3900---------(1)
x +3y = 1300-----------(2)
by taking eq 1
y=0
3 (x) + 6(0)= 3900
3x+ 0=3900
3x = 3900
x= 3900÷3 =1300
x =0
0 + 6y = 3900
y= 650
x--- 1300 , 0
y--- 0 , 650
and doing the same with eq (2)
let the cost of each ball=Y
atq
3x +6y =3900---------(1)
x +3y = 1300-----------(2)
by taking eq 1
y=0
3 (x) + 6(0)= 3900
3x+ 0=3900
3x = 3900
x= 3900÷3 =1300
x =0
0 + 6y = 3900
y= 650
x--- 1300 , 0
y--- 0 , 650
and doing the same with eq (2)
Dpkyathi:
tq dear
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