The coach of a cricket team buys 7 bats & 6 balls for Rs3800. Later, he buys 3 bats & 5 balls for Rs1750. Find the cost of each bat & each ball.
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Let cost of each bat = Rs x
Cost of each ball = Rs y
Given that coach of a cricket team buys 7 bats and 6 balls for Rs 3800.
So that 7x + 6y = 3800
6y = 3800 – 7x
Divide by 6 we get
y = (3800 – 7x) /6 … (1)
Given that she buys 3 bats and 5 balls for Rs 1750.so that
3x + 5y = 1750
Plug the value of y
3x + 5 ((3800 – 7x) /6) = 1750
Multiply by 6 we get
18 x + 19000 – 35 x = 10500
-17x =10500 - 19000
-17x = -8500
x = - 8500 / - 17
x = 500
Plug this value in equation first we get
y = ( 3800 – 7 * 500) / 6
y = 300/6
y = 50
Hence cost of each bat = Rs 500 and cost of each balls is Rs 50
Cost of each ball = Rs y
Given that coach of a cricket team buys 7 bats and 6 balls for Rs 3800.
So that 7x + 6y = 3800
6y = 3800 – 7x
Divide by 6 we get
y = (3800 – 7x) /6 … (1)
Given that she buys 3 bats and 5 balls for Rs 1750.so that
3x + 5y = 1750
Plug the value of y
3x + 5 ((3800 – 7x) /6) = 1750
Multiply by 6 we get
18 x + 19000 – 35 x = 10500
-17x =10500 - 19000
-17x = -8500
x = - 8500 / - 17
x = 500
Plug this value in equation first we get
y = ( 3800 – 7 * 500) / 6
y = 300/6
y = 50
Hence cost of each bat = Rs 500 and cost of each balls is Rs 50
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