Question

The coach of a cricket team buys 7 bats and 6 balls for 13200. Later,
he buys 3 bats and 5 balls for 5900. Find the cost of each bat and
each ball.
h ball be​

Answer 1

Answer:

Let the number of bats be x and number of balls be y

Case 1:

ATQ, 7x+6y=13200........1

Case 2:

ATQ,3x+5y=5900..........2

Multiply equation 1 by 5 and equation 2 by 6

5(7x+6y=13200)

35x+30y=66000..........3

6(3x+5y=5900)

18x+30y=35400...........4

Solving equation 3 and equation 4

35x+30y=66000

18x+30y=35400

-      -        -

17x=30600

x=30600/17

x=1800

Substitute x=1800 in equation 2

3x1800+5y=5900

5400+5y=5900

5y=5900-5400

5y=500

y=100

Therefore, the cost of 1 bat is 1800 Rs    and the cost of 1 ball is 100Rs

Hope that was helpful

Answer 2

Step-by-step explanation:

$\huge \bf \purple{❥︎}Given:$

Cost of 7 bats and 6 balls is Rs 13200.

Cost of 3 bats and 5 balls is Rs 5900.

To Find:

What is the cost of each bat and ball ?

Solution: Let the cost of each bat and ball be Rs x and y respectively.

➙ Cost of 7 bats = Rs 7x

➙ Cost of 6 balls = Rs 6y

$\bf\implies{\rm }7x + 6y = 13200$

$\bf \red{Equation \: 1}$

$\bf \purple{Now , \: In \: second \: case}$

➙ Cost of 3 bats = Rs 3x

➙ Cost of 5 balls = Rs 5y

$\bf\implies{\rm }3x + 5y = 5900$

$\bf \red{Equation \: 2}$

[ Multiplying 5 in equation 1 and 6 in equation 2 ]

➯ (7x + 6y) 5 = 13200 × 5

35x + 30y = 66000ㅤㅤㅤeqⁿ i

➯ (3x + 5y) 6 = 5900 × 6

18x + 30y = 35400ㅤㅤeqⁿ ii

ㅤㅤㅤㅤㅤ35x + 30y = 66000

ㅤㅤㅤㅤㅤ18x + 30y = 35400

ㅤㅤㅤㅤㅤ–ㅤㅤ–ㅤㅤ–

ㅤㅤㅤㅤ━━━━━━━━━━━━━━━

ㅤㅤㅤㅤㅤ17x = 30600

∴ x = 30600/17 = 1800

Now putting the value of x in equation 1.

$\bf \pink{\implies{\rm } 7 × 1800 + 6y = 13200}$

$\bf \orange{\implies{\rm } 6y = 13200 – 12600}$

$\bf \blue{\implies{\rm } y = 600/6}$

$\bf \purple{\implies{\rm } y = 100}$

Hence, the cost of each bat and ball is Rs 1800 & Rs 100 respectively.

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